By Steve B.
I needed to make a small conical shape from a flat piece of plastic. I had replaced the small jet fan in my Kyosho Jet Vision since the original fan shucked a few blades on takeoff (FOD). The new fan was bigger so it needed an adapter to fit between the fan and rear half of the exhaust cone. I could do it with trial and error but I wondered if I could figure out the math and create it in my drawing program, and I did.
I’m sure there are any number of places online that have this already figured out, where you can simply input your measurements and voila you get the answer. I didn’t look. I wanted to see how it was done. My only external source was my lovely retired middle school math teacher wife, Alice, who provided some of the basic formulas I had forgotten. Although, when I had a question, I did have to raise my hand and wait my turn. . .
Remember sitting in Middle School (Junior High) Math class and wondering what you’ll ever use this stuff for? Well, this is a great example where you can use both Geometry and Algebra. Sound like fun?
A typical exhaust cone will look something like these. The long one fits my Avanti jet and the other is for my Jet Vision:
My drawings were done in a computer drafting program. You can also do it by hand using a compass, protractor and straight edge. You may need to commandeer the dining room table if your workbench is loaded with stuff, like mine.
Using my Avanti jet as an example, I created this drawing. I know the Avanti does not need a tail cone, I just used it for an example. The calculations are below:
This is the math used to create the drawing:
What we know:
<1 = <2 (Angle 1 = Angle 2)
R2 = R1 + Lc (Radius 2 = Radius 1 + Length of Cone). (R1 & R2 are radii used for the layout above.)
Arc1 (Arc length 1) see just below
Arc2 (Arc length 2)
The arcs lengths are the circumferences of the ends of the cone. For their radii, just measure the diameters of the fan and outlet and divide by 2. (ro1 = radius of outlet, rf2 = radius of fan.) The arc lengths are:
eq. 1 Arc1 = 2π ro1 and Arc2 = 2π rf2
Now all we need to find are <1 & <2 and R1 & R2 in order to create the layout. We know the relationships between the angles and between the radii. This gives us only two unknowns.
Now we just need two equations. Solve for one unknown in one equation, substitute that into the other equation and solve for the other unknown.
eq. 1a (<1÷360) 2π R1 = Arc1
eq. 1b (<2÷360) 2π (R1 + Lc) = Arc2
Lets solve for R1 in eq. 1a:
eq. 1c R1 = Arc1÷(.0175<1)
Substitute that into eq. 1b and we get:
(<2/360) 2π (Arc1÷(.0175<1) + Lc) = Arc2
Lets solve for the angles (<1 = <2):
(.0175<2 (Arc1÷(.0175)<1 + Lc) = Arc2
Arc1 + .0175<2 Lc = Arc2
eq. 2 <1 = <2 = (Arc2 – Arc1)÷(.0175Lc)
The Arcs and the Cone Length are measured quantities, so substitute them in to find the angle.
Now find R1 by substituting the angle into either eq1c.
eq. 3 R1 = Arc1÷(.0175<1)
Here are the numbers needed to make the drawing above:
ro1 = 35mm, rf2 = 41.5mm
Lc = 365mm
From eq1: Arc1 = 2π ro1 = 220mm, Arc2 = 2π rf2= 261mm
From eq2: <1 = <2 = 6.419 Deg
From eq3: R1 = 1958mm, R2 = R1 + Lc = 1958 + 365 = 2323mm
These highlighted values are what you need to draw your exhaust cone.